Daniel Lowrie, our Host, told me this years ago. I can't forget it now that I've heard it.

All People Seem To Need Dan Physically.

I only used ITPro.TV for my Network+.
For the Project+, I also read the book by Sybex.
For the Healthcare IT Technician I just sat for it.
Don explaining IP and Subnetting was instrumental.

Thanks!

Gary,
The CSMA/CA on a wireless doesn't prevent collisions...I know strange,right. In a wireless, when two devices send out the jamming signal simultaneously, they will hear each other's jamming and do the default behavior--both computers will stop trying to send a jam and wait a random period of time before trying to send a jam again indicating it's readiness to transmit. So no ACK is needed.
Now, even though an ACK is not required before two computers try to resend. In a wireless scenario, transmission collisions are minimized because every transmission requires an ACK. When the sending device doesn't receive an ACK, it will re-transmit the last transmission again. This is because no ACK indicates a failure in the transmission.
Cordially,
Ronnie Wong
Host, ITProTV

damewoodr,
Glad you're enjoying ITProTV and you're asking a great question!
The answer lies in your subnet mask! If you were to write out your subnetmask of the /22 = 255.255.252.0 This last octet is our only real concern here.
If you were to begin with a 10.0.0.0/8
One network 10.0.0.0, 16,777,214 hosts
With your subnet mask of /22, this means that you can have 2^14 number of subnets= 16,384 possible subnets from that 10.0.0.0/8 network. (I will not do all of them but I will set the pattern of where this begins.
1st - 10.0.0.0/22 00001010.00000000.00000000.00000000/22
2nd - 10.0.4.0/22 00001010.00000000.00000100.00000000/22
3rd - 10.0.8.0/22 00001010.00000000.00001000.00000000/22
4th - 10.0.0.0/22 00001010.00000000.00001100.00000000/22
5th - 10.0.4.0/22 00001010.00000000.00010000.00000000/22
6th - 10.0.8.0/22 00001010.00000000.00010100.00000000/22
...
(notice the interval of 4 in between the subnets--this comes from the fact that we are not concerned with 10 hosts bits) but we are concered with the FIRST 22 bits.)
If you were to copy and paste the above binary into a word proccessor and continue to work it all the way through to 10.55.40.0/22...
Xst - 10.0.40.0/22 00001010.00000000.00101000.00000000/22
Xnd - 10.0.44.0/22 00001010.00000000.00101100.00000000/22

Xrd - 10.0.48.0/22 00001010.00000000.00110000.00000000/22
Xth - 10.0.52.0/22 00001010.00000000.00110100.00000000/22
The /22 give you an interval of 4 because the 22nd bit is in the 3rd octet with a place value of 4. So your network ID numbers will always be increments of 4.
Hope this explaination helped you.
Cordially,
Ronnie Wong
Host, ITProTV

shlomgad,
I saw this post just yesterday, but we believe the link is now fixed.
I browsed to it from the Course Library, Comptia, Network+ and the overview page. There are now two links, one for the main link and the one for (Part2). Yesterday, there was the same link for both. Hopefully, we've fixed this for you.
Please let us know if you have any subnetting questions that we can help you with in your studies.
Cordially,
Ronnie Wong
Host, ITProTV